2[2(2.25-1y)+2(y-2)]=1

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Solution for 2[2(2.25-1y)+2(y-2)]=1 equation: 


Simplifying
2[2(2.25 + -1y) + 2(y + -2)] = 1
2[(2.25 * 2 + -1y * 2) + 2(y + -2)] = 1
2[(4.5 + -2y) + 2(y + -2)] = 1

Reorder the terms:
2[4.5 + -2y + 2(-2 + y)] = 1
2[4.5 + -2y + (-2 * 2 + y * 2)] = 1
2[4.5 + -2y + (-4 + 2y)] = 1

Reorder the terms:
2[4.5 + -4 + -2y + 2y] = 1

Combine like terms: 4.5 + -4 = 0.5
2[0.5 + -2y + 2y] = 1

Combine like terms: -2y + 2y = 0
2[0.5 + 0] = 1
2[0.5] = 1

Multiply 2 * 0.5
1 = 1

Add '-1' to each side of the equation.
1 + -1 = 1 + -1

Combine like terms: 1 + -1 = 0
0 = 1 + -1

Combine like terms: 1 + -1 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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